check if it contains only vowels. Using Python
Posted on | Wednesday, 17 May 2023 | No Comments
Given a string, check if it contains only vowels.
Input Format
Input contains a string S, consisting of lowercase and uppercase characters.
Constraints
1 <= len(S) <= 100
Output Format
Print "Yes" if string contains only vowels, "No" Otherwise.
Sample Input 0
SmartInterviews
Sample Output 0
Novcount = 0;
ccount = 0;
str = input()
str = str.lower();
for i in range(0,len(str)):
if str[i] in ('a',"e","i","o","u"):
vcount = vcount + 1;
elif (str[i] >= 'a' and str[i] <= 'z'):
ccount = ccount + 1;
if ccount==0:
print("Yes")
else :
print("No")
Print unique elements of the array in the same order as they appear in the input. Using Python
Posted on | Sunday, 14 May 2023 | No Comments
Print unique elements of the array in the same order as they appear in the input.
Note: Do not use any inbuilt functions/libraries for your main logic.
Input Format
First line of input contains a single integer N - the size of array and second line contains array elements.
Constraints
1 <= N <= 100
0 <= ar[i] <= 109
Output Format
Print unique elements of the array.
Sample Input 0
7
5 4 10 9 21 4 10
Sample Output 0
5 9 21k=int(input())
b=[]
a=list(map(int,input().split()))
for i in range(k):
for j in range(k):
if a[j]==a[i] and j!=i:
b.append(a[i])
r = [i for i in a if i not in b]
for i in range(len(r)):
print(r[i],end=" ")