Car Range Code Chef.

Posted on | Friday, 19 May 2023 | No Comments

Problem

The fuel economy of a car is the distance which it can travel on one litre of fuel.

The base fuel economy (i.e, its fuel economy when there is only one person - the driver - in the car) of a certain car is $�$ kilometres per litre. It was also observed that every extra passenger in the car decreases the fuel economy by $1$ kilometre per litre.

$�$ people want to take this car for a journey. They know that the car currently has $�$ litres of fuel in its tank.

What is the maximum distance this car can travel under the given conditions, assuming that all $�$ people always stay in the car and no refuelling can be done?

Note that among the $�$ people is also a driver, i.e, there are exactly $�$ people in the car.

Input Format

• The first line of input contains a single integer $�$, denoting the number of test cases. The description of $�$ test cases follows.
• Each test case consists of a single line of input, containing three space-separated integers $�,�$, and $�$ - the number of people, base fuel economy, and amount of fuel present in the car, respectively.

Output Format

For each test case, output a single line containing one integer - the maximum distance that the car can travel.

Constraints

Sample 1:

3
5 10 20
1 6 10
4 6 1

120
60
3

Explanation:

Test Case $1$: There are $5$ people in the car, and its base fuel economy is $10$. Thus, its effective fuel economy is $10-4=6$, since there are $4$ people present other than the driver. There are $20$ litres of fuel in the car, so the maximum distance that can be travelled is $6\cdot 20=120$.

Test Case $2$: The effective fuel economy is $6$, and the maximum distance that can be travelled is $6\cdot 10=60$.

Test Case $3$: The effective fuel economy is $3$, and the maximum distance that can be travelled is $3\cdot 1=3$.

CODE:

for i in range(int(input())):

    a,b,c=map(int,input().split())

    if a>1:

        print((b-(a-1))*c)

    else:

        print(b*c)

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